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janata Bank Ltd. Recruitment Test for Execute Office Examination Held On: 21.04.2017 || 2017

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Mathematics ( A- D)

A number when divided successively by 4 and 5 leaves remainders 1 and 4 respectively, when it is successively divided by 5 and 4, what will be the respective remainders?

প্রশ্নে বলা হচ্ছে যে, কোনো সংখ্যাকে যখন 4 এবং তার ভাগফলকে 5 দ্বারা ভাগ করলে ভাগশেষ যথাক্রমে 1 এবং 4 থাকে। সংখ্যাটিকে 5 এবং তার ভাগফলকে 4 দ্বারা ভাগ করা হলে ভাগশেষ কত থাকবে?

Let, the number be x

and the quotient be y

So, x = 4y + 1 ……………….. (i)

Again, the quotient of y and z

So, y= 5z+4………………….(ii)

If z = 1 then y = 5.1 +4= 5+4= 9

From (i) x = 4 x 9 = 36

x= 36+1=37

Now, $37 \div 5 = 7 \frac{5}{2} = 2$

again, $4 \div 7 = 1 \frac{4}{3} = 3$

ans. The respective remainders will be 2 & 3.

Mathematics ( A- D)

A contractor undertakes to do a piece of work in 40 days . he engages 100 men at the beginning and 100 more after 35 days and completes the work in stipulated time. If he had not engaged the additional men, how many days behind schedule would it be finished?

প্রশ্নে বলা হচ্ছে যে, একজন লোক একটি কাজ 40 দিনে করার চুক্তি নিল। সে শুরুতে 100 জন লোক নিয়োগ করলো এবং 35 দিন পর সে আরো 100 জন লোক করলো এবং চুক্তিকৃত দিনে কাজটি সমাধান করে। সে যদি অতিরিক্ত 100 জন লোক নিয়োগ না করতো, তাহলে কাজটি কয়দিন পরে শেষ হতো?

$[(100 \times 35) + (200 \times 5)]$ Men can finish the work 1 day.

That mans, 4, 500 men can finish the work in = 1 day.

1 men can finish the work in= $\frac{4500 \times 1}{1}$ days

100 men can finish the work in = $\frac{4500}{100} = 45$ days

It would be finished behind schedule = 45-40=5 days ans.

Mathematics ( A- D)

In a certain office 1/3 of the workers are women, ½ of the women are married and 1/3 of the married women have children . If ¾ of the men are married and 2/3 of the married men have children what part of workers are without children?

Given, women = $\frac{1}{3}$

Men = $1 - \frac{1}{3} = \frac{3 - 1}{3} = \frac{2}{3}$

Married women = $\frac{1}{3} o f \frac{1}{2} = \frac{1}{6}$ of whole office is married women.

Married women who have children = $\frac{1}{6} o f \frac{1}{3} = \frac{1}{18}$

Married men= $\frac{2}{3} o f \frac{3}{4} = \frac{1}{2}$ of whole workers

Married men who have children = $\frac{1}{2} o f \frac{2}{3} = \frac{1}{3}$ of married men.

Married workers who have children = $(\frac{1}{18} + \frac{1}{3}) = \frac{1 + 6}{18} = \frac{7}{18}$ Part of whole workers

$(1 - \frac{7}{18}) = \frac{18 - 7}{18} = \frac{11}{18}$ Worker does not have children. ans.

Mathematics ( A- D)

The average weight of three mane A, B and C is 84 kg. Another man D joins the groups and the average now becomes 80 kg. If another man E, whose weight is 3 kg more than that of D, replace , A, then average weight of B, C, D and E becomes 79 Kb. What is the weight of A?

Avg. weight of A, B, C is 84kg.

Sum = $84 \times 3 = 252 k g$ .

Avg. weight of A, B, C, D is 80kg.

$S u m = 80 \times 4 = 320 k g .$

D's weight=320-252= 68kg.

Weight of E = 68+3=71kg.

Weight of A+B+C+D+E=320+71=391 kg.

& the weight of B+C+D+E= 79x4=316 kg.

Weight of A= 391 - 316= 75 kg. ans.

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janata Bank Ltd. Recruitment Test for Execute Office Examination Held On: 21.04.2017 || 2017

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