cosec θ cos (90° – θ) এর মান কত?

\frac{1}{\sqrt{2}}

1

2

\frac{\sqrt{3}}{2}

\frac{1}{\sqrt{2}}

1

2

\frac{\sqrt{3}}{2}

2.

$c o t \frac{π}{4} \sin \frac{π}{4} \cos \frac{π}{4} \tan \frac{π}{4} =$ কত?

\frac{1}{\sqrt{2}}

\frac{1}{2}

1

2

\frac{1}{\sqrt{2}}

\frac{1}{2}

1

2

3.

$\frac{\cos A}{\sin A} = \frac{1}{\sqrt{3}}$ হলে নিচের কোনটি A এর মান?

30°

45°

60°

0°

30°

45°

60°

0°

4.

$\sin 45 ° = \sqrt{2 A}$ হলে, A = কত?

1

\frac{1}{2}

\frac{1}{\sqrt{2}}

\frac{1}{\sqrt{3}}

1

\frac{1}{2}

\frac{1}{\sqrt{2}}

\frac{1}{\sqrt{3}}

5.

sin θ এর মান কত?

\frac{1}{\sqrt{3}}

\frac{\sqrt{2}}{\sqrt{3}}

\frac{1}{\sqrt{2}}

\sqrt{2}

\frac{1}{\sqrt{3}}

\frac{\sqrt{2}}{\sqrt{3}}

\frac{1}{\sqrt{2}}

\sqrt{2}

6.

$\tan θ = \frac{1}{\sqrt{3}}$ হলে, sin θ এর মান কোনটি?

\frac{\sqrt{3}}{2}

\frac{1}{2}

\frac{1}{3}

০

\frac{\sqrt{3}}{2}

\frac{1}{2}

\frac{1}{3}

০

7.

$\tan 2 θ = \sqrt{3}$ হলে θ = কত?

0°

30°

45°

60°

0°

30°

45°

60°

8.

θ = 30° হলে, tan 2θ = কত?

\sqrt{3}

\frac{1}{\sqrt{3}}

1

০

\sqrt{3}

\frac{1}{\sqrt{3}}

1

০

9.

cos 60°. sec 60° = কত?

\frac{1}{2}

2

1

\frac{1}{\sqrt{2}}

\frac{1}{2}

2

1

\frac{1}{\sqrt{2}}

10.

1 + sin 30° = কত?

\frac{1}{2}

\frac{3}{2}

\frac{1}{\sqrt{2}}

\frac{1 + \sqrt{2}}{2}

\frac{1}{2}

\frac{3}{2}

\frac{1}{\sqrt{2}}

\frac{1 + \sqrt{2}}{2}

11.

tan 30°. cot 30° = কত?

\sqrt{3}

\frac{1}{\sqrt{3}}

\frac{1}{3}

1

\sqrt{3}

\frac{1}{\sqrt{3}}

\frac{1}{3}

1

12.

sin 30° + sin² 30° = কত?

\frac{1}{2}

\frac{1}{4}

\frac{3}{4}

\frac{1}{8}

\frac{1}{2}

\frac{1}{4}

\frac{3}{4}

\frac{1}{8}

13.

যদি $\tan (90 ° - A) = \frac{4}{3}$ হয়, তাহলে, cos A =?

\frac{5}{4}

\frac{4}{5}

\frac{5}{3}

\frac{3}{4}

\frac{5}{4}

\frac{4}{5}

\frac{5}{3}

\frac{3}{4}

14.

60° এর পূরক কোণের cos অনুপাতের মান কত?

\frac{1}{2}

\frac{\sqrt{3}}{2}

1

০

\frac{1}{2}

\frac{\sqrt{3}}{2}

1

০

15.

$\cos θ = \frac{1}{2}$ হলে $\cos (90 ° - θ)$ এর মান কত?

1

\frac{1}{\sqrt{2}}

\frac{\sqrt{3}}{2}

০

1

\frac{1}{\sqrt{2}}

\frac{\sqrt{3}}{2}

০

16.

$\cos (90 ° - A) \tan (90 ° - A) = ?$

sin A

cos A

sec A

cosec A