A depositor deposited Tk. 4,000 at x% simple interest and Tk. 5,000 at y% simple interest. He received annual interest of Tk. 320 on his deposited amounts at the year end. If he could deposit Tk. 5,000 at x% simple interest and Tk. 4,000 at y % simple interest, he would receive annual interest of Tk. 310. Find the value of x and y.
we know, I=prt100, where I=Interest; p=Principal; T=time Here, according to question for 1st & 2nd part 4000×x×1100+5000×y×1100=320.......(i) and, 5000×x×1100+4000×x×1100=310.......(ii) Now, from (i) we have, 4000x100+5000y100=320 ⇒4000x+5000y100=320⇒4000x+5000y=320×100⇒4x+5y=32........(iii)again, from (ii) we have, 5000x100+4000y100=310⇒5000x+4000y100=310⇒5000x+4000y=310×100⇒1000(5x+4y)=31×1000⇒5x+4y=31.......(iv) Now, we have (iii)×4⇒16x+20y=128(iv)×5⇒25x+20y=155⇒-9x=-27x=-27-9Now, putting x=3 in (iii)4×3+5y=32⇒12+5y=32⇒5y=32-12⇒5y=20⇒y=204=4
The required value, x= 3 & y = 4 .
Selling 12 candies at a price of 1, 18 vids a loss of x% and selling 12 candies at a price of Tk. 12 yields a profit of x%. What is the value of x?
Repeat: Southeast bank (PO) 2017