Sonali Bank Ltd. Recruitment Test for Officer (Cash) Examination Held On: 18.05.2018 || 2018

C will get as profit =$1-\left(\frac{3+8}{24}\right)=1-\frac{11}{24}=\frac{24-11}{24}=\frac{13}{24}$ Part 

A, B & C investment ratio $\frac{1}{8} : \frac{1}{3} : \frac{13}{24} = 3 : 8 : 13$ [Multiplying by 24]
Now, we know A, B and C's profits will be distributed according to their investment Now, let, A's investment is x Tk. & B's investment is y Tk.
and C's investment is 1,560 Tk.

 According to question,

$$\begin{gathered} \frac{x\times 4}{1560\times 8}=\frac{3}{13} \\ x=\frac{3\times 1560\times 8}{13\times 4}=720 \\ again, \frac{y\times 6}{x\times 4}=\frac{8}{3} \\ \Rightarrow \frac{y\times 6}{720\times 4}=\frac{8}{3} \\ y= \frac{8\times 720\times 4}{6\times 3}=1280 \end{gathered}$$

A and B invested respectively 720 Tk. and 1,280 Tk. respectively.

A can produce in 12 minutes x pound of peanut butter
A can produce in 1 minute $\frac{ x}{ 12}$ pound of peanut butter
Again, B can produce in 18 minutes x pound of peanut butter

B can produce in 1 minute $\frac{ x}{ 18}$ pound of peanut butter

So, in 1 minute (A + B) can produce = $\left(\frac{x}{12}+\frac{x}{18}\right)=\left(\frac{3x+2x}{36}\right)=\frac{5x}{36}$ pounds.

Now, $\frac{5x}{36}$ pounds can be produced by (A + B) in = 1 minute 
x pounds can be produced by (A + B) in = $\frac{36\times x}{5x}=7.2$ minutes = 7 minutes 12 seconds. (ans.)

Relative speed white running in opposite direction 12 

$= (75+60) kmph : =\left(135\times \frac{5}{18}\right) m{s}^{-1}=\frac{75}{2} m{s}^{-1}$

Again, relative speed while running in same direction 

$=(75-60) kmph=15 kmph =\left(15\times \frac{5}{18}\right) m{s}^{-1}=\frac{25}{6} m{s}^{-1}$

As we know, velocity =$\frac{Dis\tan ce }{ Time}$ 
$Dis\tan ce = Velocity\times Time$
Lengths of the both trains =$\left(\frac{75}{2}\times 8\right)=300$ meter

Now, as the faster train exceeds the slower train in the same direction in $33\frac{1}{2}$ seconds.

The length of the slower train = $\left(\frac{25}{6}\times 33.5\right)=131.25$ meter.

The length of the faster train =$300-131.25 = 168.75$ meter

(ans.) Faster train 168.75 meter & slower train 131.25 meter.

Width of the first garden = $\frac{ 600}{ 40}=15$ feet 
Width of the second garden = $15\times 2=30$  feet

Area of the second garden will be = $\frac{600}{2}=300$ square feet

Length of the second garden =  $\frac{300 }{30}=10$ feet

So, we have got, the length of the first garden is 40 feet and the length of the second garden is 10 feet.
And the width of the first garden is 15 feet and the width of the second garden is 30 feet
Perimeter of the first garden = $2 (40+15 )=2\times 55=110$ meter 

And Perimeter of the second garden = $2(10 + 30)=2\times 40=80$ meter 

Ratio of the perimeter of the two garden = $110 : 80 = 11 : 8$ 

Given, total students = 16 

As, the number of boys is the multiple of 5

So, the possible number of boys may be 5, 10, 15 

And the number of girls is the multiple of 3

So, the possible number of girls may be 3, 6, 9, 12, 15 

According to the question,

The number of boys may be = 10 and the number of girls may be = 6 

The number of boys taller than the shortest girl = $10\times \frac{1}{5} = 2$

And the number of girls shorter than the tallest boy =$6\times \frac{1}{3} = 2$

Here, there is 1 shortest boy and 1 tallest girl. The number of students taller than the shortest girl and the shorter than the tallest boy =16-(2+2+1+1) = 10

Required percentage = $\left(\frac{10}{16}\times 100\right)\%=62.5$