A jar contains 'x' liters of milk, a seller withdraws 25 liter of it and sells it at Tk. 20 per liter. He then replaces it water. He repeated the process total three times. Every time while selling he reduces selling price by Tk. 2. After this process milk left in the mixture is only 108 liters so he decided to sell the entire mixture at Tk. 15 per liter. Then how much profit did he earn if bought milk at Tk. 20 per liter?

Created: 3 months ago | Updated: 3 months ago

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প্রশ্নে বলা হচ্ছে যে, একটি পাত্রে ‘x' লিটার দুধ রয়েছে। একজন দুধ বিক্রেতা পাত্র হতে 25 লিটার দুধ সরিয়ে নিয়ে তা 20 টাকা দরে বিক্রয় করলো। তারপর সে ঐ পাত্রে 25 লিটার পানি মেশালো। সে মোট 3 বার এই কাজটি করলো। প্রতিবারে বিক্রয়ের সময় সে বিক্রয়মূল্য 2 টাকা করে কমালো। এই কাজ করার পর তার নিকট 108 লিটার দুধ থাকলো এবং সে এই 108 লিটার দুধ 15 টাকা দরে বিক্রয়ের সিদ্ধান্ত নিল। প্রতি লিটার দুধ তার 20 টাকা দরে কেনা থাকলে সে মোট কত টাকা লাভ করলো?

এখানে মূলত ঐ পাত্রে প্রথমে 108 লিটার দুধ ছিল। কারণ, সে প্রতিবারে 25 লিটার দুধকে 25 লিটার পানি দ্বারা Replace করেছে, ফলে মোট দুধের পরিমাণ অপরিবর্তিত ছিল ।

আসুন এবার অঙ্কের সমাধানে যাওয়া যাকঃ

He sells first 25 liters at Tk. 20

∴ Selling price of first 25 liters of milk $= 25 \times 20 = T k . 500$

sells second 25 liters at Tk. 18

Selling price of second 25 liters of milk $= 25 \times 18 = T k . 450$

He sells third 25 liters at Tk. 16

∴ Selling price of third 25 liters of milk $= 25 \times 16 = T k . 400$

Now, total 108 liters of milk he sells at Tk. 15

∴ Selling price of remaining 108 liters of milk $= 108 \times 15 = T k . 1, 620$

His total selling price = 500 + 450 + 400+ 1,620 = Tk. 2,970

His total cost price $= 108 \times 20 = T k . 2, 160$

∴ Profit earned from selling milk = 2,970 - 2,160 = Tk. 810

ans. He earned as profit Tk. 810

3 months ago

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