Sonali & Janata Bank Ltd. Recruitment Test for Senior Officer (IT/ICT)) Examination Held On: 29.06.2018 || 2018

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Given, total rods = 75

Color Total TwistedClear
Blue 352510
Red403010

Now, we will find the probability.

A. Probability of a blue rod from the box = Total blue rodsTotal rods=3575=715

B. Probability of a clear rod from the box = Total blue rodsTotal rods=10+1075=2075=415

C. Probability of a blue twisted rod = Total blue rodsTotal rods=2575=13

D. Probability of a clear red rod =  Total blue rodsTotal rods=1075=215

E. Probability of a twisted rod = Total blue rodsTotal rods=25+3075=5575=1115 

Let, A took x seconds
B took (170-x) seconds.
According to question, 

340-2x-10+170-x=170330=3x3x=330x=3003=110A=110

A took 110 seconds and B took (170-110)= 60 seconds.

Let, Fahim's age be x year

Shakib is 2x years old.

4 years ago Fahim was (x-4) years old and 4 years ago Shakib was (2x-4) years old

According to question

3x-4-6=2x-43x-12-6=2x-43x-18=2x-43x-2x=18-4=14x=14 

After 2 years, Fahim will be = 14+2 = 16 years old 

And Shakib will be = 2 ×14) + 2 = 28+ 2 = 30  years old

Total amount of charity =  20 × 4 = 80 Tk.

Here, maximum 3 students can give = 25 Tk.

Total = 3 × 25 = 75 Tk.

Minimum amount contributed by one student = 80-75 =5 Tk.

The sum of 15 consecutive integers will 88.

only when there are some positive and negative consecutive integers. 

So, we let, the numbers are (x-7), (x-6), (x-5), (x-4) (x-3), (x-2) (x-1) x, (x + 1), (x+2), (x+3), (x+4), (x+5), (x+6) (x+7).

According to question 

x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)+(x+6)+(x+7)+(x-7) + (x 6) + (x 5) + (x  4)+(x-3)+(x-2)+(x-1)=88
 15x+28-28 = 88 15x = 88x=8815

The largest number is (x+7)= 88 15+7=88+10515=19315
But, here 19315 is not a integer. 

So the data given in the question may not be consistent.

Solve the following inequalities:
6.

x2-12x+27<0

Created: 2 months ago | Updated: 9 hours ago

x2-12x+27<0x2-9x-3x+27<0xx-9-3x-3<0Here, if we take x<3Then, x2-12x+27<0 will not be true and if we take x<9. So, x must lie between 3<x<9,Because for each value between 3<x<9, (x2-12x+27)<0 will be true.ans. 3 <x<9.

Solve the following inequalities:
7.

x2-13x+400

Created: 2 months ago | Updated: 9 hours ago

x2-13x+400 x2-8x-5x+400 x(x-8)-5(x-8)0  (x-8) (x-5)0 Here, the product of (x-8) and (x-5) is grater than zero or equal to zero.So the value of these must be both positive or negative.When both positive, (x-8)0  x>8; (x-5)0x5  [It is not true] When both negative, -(x-8)0  x8;  [It is not true] -(x-5)0 x5; So, the range x8 Or, x5.

The number of 10 seat room = x 

The number of 20 seat room = 40- x

According to question

10x+20(40-x) = 600   10x+800- 20x = 600  -10x=600-800=-200x=-200-10 =20 

Number of 10 seat room = 20 and number of 20 seat room = 40-20=20. 

The ratio of the number of 10 seat room to the number of 20 seat room = 20 : 20= 1 : 1. ans.

Given, total football players 85

Do not score a goal = 85 - 42 = 43 players

Do not receive a yellow card = 85-54 = 31 

players Do not score a goal or don't receive yellow card or do not do either = 43 +31-5=69

Number of players who scored a goal and received a yellow end = 85 - 69 = 16

Required fraction = 16/85 ans