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The sum of 15 consecutive integers is 88. What is the largest of these integers?

Created: 2 months ago | Updated: 2 months ago

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The sum of 15 consecutive integers will 88.

only when there are some positive and negative consecutive integers.

So, we let, the numbers are $(x - 7), (x - 6), (x - 5), (x - 4) (x - 3), (x - 2) (x - 1) x, (x + 1), (x + 2), (x + 3), (x + 4), (x + 5), (x + 6) (x + 7) .$

According to question

$x + (x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) + (x + 6) + (x + 7) + (x - 7) + (x - 6) + (x - 5) + (x - 4) + (x - 3) + (x - 2) + (x - 1) = 88$
$\Rightarrow 15 x + 28 - 28 = 88 \Rightarrow 15 x = 88 ∴ x = \frac{88}{15}$

The largest number is $(x + 7) = \frac{88}{15} + 7 = \frac{88 + 105}{15} = \frac{193}{15}$
But, here $\frac{193}{15}$ is not a integer.

So the data given in the question may not be consistent.

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A box contains 75 rods; 35 are blue and 25 of these blue rods are twisted at the bottom. Th rest of them are red and 30 of the red ones are twisted. The rods that are not twisted are clear, What is the probability of drawing?

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Solve the following inequalities:

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The sum of 15 consecutive integers is 88. What is the largest of these integers?

Related Questions

A box contains 75 rods; 35 are blue and 25 of these blue rods are twisted at the bottom. Th rest of them are red and 30 of the red ones are twisted. The rods that are not twisted are clear, What is the probability of drawing?

Algebra ( বীজগণিত)

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Solve the following inequalities:

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