1 man's 1 day's work= 116×24=1384 part

1 woman's I day's work= 132×24 =1768par

Work done in 12 days by 16 and 16 women

=1216384+16768=12124+148=12+14=2+14=34 part 

Remaining work = 1-34=4-34=14 part 

Again work done in 2 days by 16 men and 16 women 

21638416768=2124+148=2+124=324=18 part 

Now remaining work= 14-18=18 part 

Now, 1384 work is done in 1 day by = 1 man

18work is done in 2 day by =384×18×12=24 men . ans

Let, the speed of the train during returning journey be x kmph 

Speed during onward journey=  (x+ 25% of x)=x+ 25x100=5x4 kmph 

Distance covered in onward journey = 8002=400 km

Time taken by the train on onward journey= 4005x4 hours [As, time= Distance/Speed]

And time by the train in returning journey = 400x hours

According to the question,

4005x4+400x =164001×45x+400x=16320x+400x=16320+400x=1616x=720 x=45 kmph 

Speed of the train in the onward journey=5x4=5×454=56.25 kmph