Solve the equation: $\frac{1}{x + 2} + \frac{1}{x + 5} = \frac{1}{x + 4} + \frac{1}{x + 3}$

Created: 3 months ago | Updated: 3 months ago

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$\frac{1}{x + 2} + \frac{1}{x + 5} = \frac{1}{x + 4} + \frac{1}{x + 3} \Rightarrow \frac{1}{x + 2} - \frac{1}{x + 4} = \frac{1}{x + 3} - \frac{1}{x + 5} \Rightarrow \frac{x + 4 - x - 2}{x^{2} + 4 x + 2 x + 8} = \frac{x + 5 - x - 3}{x^{2} + 5 x + 3 x + 15} \Rightarrow \frac{2}{x^{2} + 6 x + 8} = \frac{2}{x^{2} + 8 x + 15} \Rightarrow \frac{1}{x^{2} + 6 x + 8} = \frac{1}{x^{2} + 8 x + 15} \Rightarrow x^{2} + 8 x + 15 = x^{2} + 6 x + 8 \Rightarrow x^{2} + 8 x - x^{2} - 6 x = 8 - 15 \Rightarrow 2 x = - 7 \Rightarrow x = \frac{- 7}{2} ∴ x = \frac{- 7}{2}$

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A, b and C can complete a piece of work in 16,32 and 48 and 48 days, respectively. They started working together but C left after working 4 days and B left 2 days before the completion of the work. How many days it took in total to complete the work?

Created: 3 months ago | Updated: 3 months ago

Job Solution Social Islami Bank Ltd Social Islamic Bank Ltd. Recruitment Test for Probationary Office Examination Held on: 19.05.2017 || 2017 গণিত

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The cost of two watches taken together is Tk. 840. If by selling one at a profit of 16% and the other at a loss of 12%, there is no loss or gain in the whole transaction, find the cost of each of the two watches.

Created: 3 months ago | Updated: 3 months ago

Job Solution Social Islami Bank Ltd Social Islamic Bank Ltd. Recruitment Test for Probationary Office Examination Held on: 19.05.2017 || 2017 গণিত

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The perimeter of a square field is equal to the perimeter of a rectangular field. Length of the rectangular field is 3 times of its width and the area 768 square meter. How many square sizes tiles of 80 centimeter wide will be required to cover the square field?

Created: 3 months ago | Updated: 3 months ago

Job Solution Social Islami Bank Ltd Social Islamic Bank Ltd. Recruitment Test for Probationary Office Examination Held on: 19.05.2017 || 2017 গণিত

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Solve the equation: 1x+2+1x+5=1x+4+1x+3

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Solve the equation: $\frac{1}{x + 2} + \frac{1}{x + 5} = \frac{1}{x + 4} + \frac{1}{x + 3}$