Solve the equations: $2 {(\frac{x + 3}{x - 3})}^{2} - 7 (\frac{x + 3}{x - 3}) + 6 = 0$

Created: 3 months ago | Updated: 3 months ago

Job Solution Rajshahi Krishi Unnayan Bank Rajshahi Krishi Unnnayan Bank Ltd Recruitment Test for Office ( Written ) 2017 Examination Held: 15.08.2017 || 2017 গণিত

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$L e t, \frac{x + 3}{x - 3} = a W e g e t, 2 a^{2} - 7 a + 6 = 0 \Rightarrow 2 a^{2} - 4 a - 3 a + 6 = 0 \Rightarrow 2 a (a - 2) - 3 (a - 2) = 0 \Rightarrow (a - 2) (2 a - 3) = 0 ∴ a = 2 o r, \frac{3}{2} S o, e i t h e r \frac{x + 3}{x - 3} = 2 \Rightarrow 2 x - 6 = x + 3 ∴ x = 9 o r, \frac{x + 3}{x - 3} = \frac{3}{2} \Rightarrow 3 x - 9 = 2 x + 6 ∴ x = 15$

So, the value of x=9 or 15 ans.

3 months ago

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Solve the equations: $2 {(\frac{x + 3}{x - 3})}^{2} - 7 (\frac{x + 3}{x - 3}) + 6 = 0$