Solve the following mathematical problems:

A, B and C can complete an work in 12, 15 and 25 days resctively. A and B started working together where area C worked with them in every third day. find the number of days required to complete the work.

Created: 4 months ago | Updated: 6 days ago

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In first 6 days, C will work just two days but A and B will work 6 days.

So total work done by them in 6 days will

= $(6 \times \frac{1}{12}) + (6 \times \frac{1}{15}) + (2 \times \frac{1}{25}) = \frac{1}{2} + \frac{2}{5} + \frac{2}{25} = \frac{25 + 20 + 4}{50} = \frac{49}{50}$

Remaining work = $1 - \frac{49}{50} = \frac{1}{50}$ part of the work.

So. (A and B) 1 day's work= $\frac{1}{12} + \frac{1}{15} = \frac{4 + 5}{60} = \frac{9}{60} = \frac{3}{20}$

In 7^th day. C will not help them. Only A and B will do the $\frac{1}{50}$ part of the work because $\frac{3}{20} > \frac{1}{50}$

Now, $\frac{3}{20}$ part of the work is done by A and B in 1 day

$\frac{1}{50}$ part of the work is done by A and B in = $\frac{20}{3} \times \frac{1}{50} = \frac{2}{15}$ day

Total work will be completed in = $(6 + \frac{2}{15}) = 6 \frac{2}{15}$ days

ans. The number of days required to complete the work is $6 \frac{2}{15}$ days

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Solve the following mathematical problems:

A, B and C can complete an work in 12, 15 and 25 days resctively. A and B started working together where area C worked with them in every third day. find the number of days required to complete the work.

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