16 women can do the work in =12 days

$\therefore$1 women can do the work in = (16$\times$12) days

$\therefore$1 women can in 1 days =$\frac{1}{12\times 16}$ part of the work

Again, 12 men can do the work in = 8 days

$\therefore$1 man can do the work in = (8 $\times$ 12) days

$\therefore$I man can in 1 days = $\frac{1}{8\times 12}$ part of the work

$\therefore$16 men's 3 day's work = $\frac{1}{8\times 12}\times 3\times 16=\frac{1}{2}$ part of the work

Remaining work =$1-\frac{1}{2}=\frac{1}{2}$

Now, number of men still working = 16-10=6

$\therefore$6 men's 1 days work = $\frac{1}{12\times 8}\times 6=\frac{1}{16}$part

And 4 men's 1 days work =$\frac{1}{12\times 16}\times 4=\frac{1}{48}$part

$\therefore$They can do in 1 day = $\frac{1}{16}+\frac{1}{48}=\frac{3+1}{48}=\frac{4}{48}=\frac{1}{12}$ part

Now, $\frac{1}{12}$part of the work is done in = 1 day

$\therefore$ $\frac{1}{2}$ part of the work is done in = $\frac{12}{2}$ = 6 days.