A train has length of 150 meters. It is passing a man who is moving at 2 km/hour in the same direction of the train, in 3 seconds. Find out the speed of the train?

Created: 1 month ago | Updated: 2 weeks ago

Job Solution Uttara Bank Ltd Uttara Bank Ltd. || PO (02-10-2021) || 2021 গণিত

$H e r e, t h e t i m e t a k e n b y t h e t r a i n t o p a s s t h e m a n i s e q u a l t o t h e t i m e t a k e n t o p a s s i t' s l e n g t h 150 m e t e r s .$

$∴ T h e s p e e d o f t h e t r a i n = \frac{D i s \tan c e c o v e r e d b y t h e t r a i n}{t i m e} = \frac{150}{3} m s^{- 1} = \frac{150}{3} \times \frac{18}{5} = 180 k m p h$

$N o w, r e l a t i v e s p e e d = S p e e d o f t r a i n - S p e e d o f m a n$

$= 180 S p e e d o f t r a i n - 2$

$∴ S p e e d o f t r a i n = 180 + 2 = 182 k m p h .$

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A train has length of 150 meters. It is passing a man who is moving at 2 km/hour in the same direction of the train, in 3 seconds. Find out the speed of the train?

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