3 coins are tossed at random, show the sample space and find the the probability of getting: 

i. One head two tails 

ii. One tail 

iii. One tail and two heads

Total sample space after tossing 3 coins randomly will be = (HHH, HHT, HTH, THH, HTT, THI, TTH, TTT),

Now, we will find the probability of getting one head and two tails:

In the sample space we can see, a total of 8 types of outcome is possible. 

Among these 8 types of outcomes, the combinations with one head and two tails are (HTT, THT TTH). That means, 3 outcomes.

So, the required probability is 3/8 ans.

(ii) Probability of getting one tail: 

Above the sample space we can see that, a total of 8 types of outcome is possible. 

Among these 1 types of outcomes, the combinations with one tail are (HHT, HTH, THH). That means, 3 outcomes

So, the required probability is 3/8 ans.

(iii) Probability of getting one tail and two heads: 

Above the sample space we can see that, a total of 8 types of outcome is possible.

Among these 8 types of outcomes, the combinations with one tail and two heads are: (HHT, HTH, THH)

i.e: 3 outcomes: So, the required probability is 3/8 ans.