In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green?

Created: 2 months ago | Updated: 1 month ago
Job Solution Combined Bank (সমন্বিত ব্যাংক) সমন্বিত ১০ ব্যাংক ও আর্থিক প্রতিষ্ঠান || অফিসার (জেনারেল) (08-03-2024) গণিত
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Total number of balls = (8 + 7 + 6) = 21
Let E = event that the ball drawn in neither blue nor green
= even that the ball drawn in red.
∴n(E)=8
∴P(E)=n(E)/n(S)=8/21 (Ans)

2 months ago
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